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If any one has some time. It would great if people could check this out. I have been asked to do a solution sheet for other labbies.

Hi Labbie
Looks good

Great - I have a new labbie working 2 days with me and some of this will help her heaps when im not in sight.


Kimmy

You're seriously underworked Labbie
Mol Wt to 1L = 1M adjust for any other
the only thing that sends me looking at books is occassionally I get asked for Normal solutions

Thanks Ocker, yes I do agree, I have been asked for normal solutions, that is some thing I did forget. Richard Morante even he did not pick that up. So thank you very much.

Under worked you are kidding, it took me 14 months to get that done. Worked on it during the refub mostly.

I shall perhaps edit it for normal solutions.

Thanks Labbie

I am Annett Stanley and have only just started in the job this term, so am very new
(I haven't done much science ) and I will find this extremely helpful along with all the other "labbies" around me

once again thanks for your time and effort to put this together for us

Annett Stanley
Calrossy School
Tamworth

Welcome Annett!
You'll find you'll settle in very quickly with the help of all the knowledgeable labbies on the site.
I don't know what we'd do without it.
Julie

Welcome to chemtalk Annett, and I am please you will find solutions handy.


Please if you see any mistakes any one let me know

Welcome to Annette.
This is by far the best place to be on a working day!

Warning!!!!!!!!!!!!!!!!!!!!!!!! please when printing it is 10 pages long, silly me you only need to print out 5 pages. Sorry and thank you Ocker

Hi
Please tell me how much of 2m hcl i need to make 1m hcl. Thanks fo rhelping me out before.
cheers

Do a search for solutions, I'll see if I can link this.

The ratio is the weaker acid divided by the stronger. Ie in this case 1 divided by 2, or 1/2. So if you want 100mls 1M acid it is 100 x 1/2 or 50mls of the 2m acid made up to 100ml distilled water.

I have to admit I am too lazy , I like to punch in numbers and answer is there

http://www.easycalculation.com/chemistr ... utions.php
http://www.handymath.com/calculators.html
http://www.graphpad.com/quickcalcs/molarityform.cfm

I've bumbed this for you Suzie,

This is the lastest Solutions, Please print the one above, as their was a few mistakes in the very first one.
Happy Easter.

Wow! Just what I needed! It's great to have something rather than the net to help make up the soultions needed!

Just looked at the chart and the first one I looked at was the copper sulfate. I think there is one little mistake with the decimal point in the conc sulfuric acid added in the 0.5M: should be 6.25ml acid not 62.5ml "0.5M 312g in 2.437.5 water add 62.5ml Conc. Sulfuric Acid for 2.5 Lt".
Sorry Labbie, hope it is an easy fix.

If the 0.1 M uses 12.5mL of sulfuric, then 0.5M needs 62.5mL.
It is correct, right??
Lada

You are correct Lada, It could be the way I put then in order. 1 Litre then 2.5 litres. Hey Ladies I am so pleased that you a checking it for me. I went over a few times, but I would love every one to check it. Then we can say its correct and use it with confindence.

Thank you so very much.